在一个游戏中,有 n 个角色,每个角色有三个属性 ai,bi,ci。
对于每一个角色 i,你可以将 ai,bi,ci 变为 (ai′,bi′,ci′)。你要将角色的差距最小化。
差距定义为 max(i=1maxnai−i=1minnai,i=1maxnbi−i=1minnbi,i=1maxnci−i=1minnci)。
Problem Description
Little Q is playing an RPG online game. In this game, there are n characters labeled by 1, 2, ⋯, n. The i-th character has three types of quotas:
- ai - The maximum points of damage he can achieve in 15 seconds.
- bi - The maximum points of damage he can achieve in 40 seconds.
- ci - The maximum points of damage he can achieve in 120 seconds.
You are the team leader working for the new balance between these n characters, aiming at bringing hope to the weak characters. For each character, your teammates have made a plan to strengthen some skills such that the three quotas may be increased as a result. Note that it is not allowed to weaken characters, because it will make their owners upset.
To make a perfect balance, you need to accept some plans and deny others such that the gap between all the n characters is minimized. Note that a plan can only be entirely accepted or entirely denied. Here, the gap is defined as
max(1≤i≤nmaxai−1≤i≤nminai,1≤i≤nmaxbi−1≤i≤nminbi,1≤i≤nmaxci−1≤i≤nminci).
Input
The first line contains a single integer T (1≤T≤100), the number of test cases. For each test case:
The first line contains a single integer n (1≤n≤100000), denoting the number of characters.
In the next n lines, the i-th line contains six integers ai, bi, ci, ai′, bi′ and ci′ (1≤ai≤ai′≤109, 1≤bi≤bi′≤109, 1≤ci≤ci′≤109), describing the quotas of the i-th character now and in plan.
It is guaranteed that the sum of all n is at most 500000.
Output
For each test case, output a single line containing an integer, denoting the optimal gap.
1
2
1 1 1 2 3 5
2 4 3 7 5 8
2